About 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol
2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol (PubChem CID 106971108) has the molecular formula C14H26N4O2
and a molecular weight of 282.39 g/mol. Its IUPAC name is 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol.
Analyze 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol with MolForge
Explore ADMET properties, 3D molecular structure, drug-likeness score, and discover similar compounds using our AI-powered platform.
Launch Full Analysis
Frequently Asked Questions
What is the IUPAC name of 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol?
The IUPAC name of 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol (CID 106971108) is 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol.
What is the SMILES notation for 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol?
The canonical SMILES for 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol is CC(C)(C)NCc1nnc(N(CCO)C2CCCC2)o1.
What is the InChIKey of 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol?
The InChIKey is ZSIBIWLCRUPBTR-UHFFFAOYSA-N. The full InChI is InChI=1S/C14H26N4O2/c1-14(2,3)15-10-12-16-17-13(20-12)18(8-9-19)11-6-4-5-7-11/h11,15,19H,4-10H2,1-3H3.
What are the key properties of 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol?
2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol has a molecular weight of 282.39 g/mol, XLogP of 1.70, 6 rotatable bonds, 2 hydrogen bond donors, and 6 hydrogen bond acceptors.
Where does this data come from?
All data for 2-[[5-[(tert-butylamino)methyl]-1,3,4-oxadiazol-2-yl]-cyclopentylamino]ethanol is sourced from PubChem (CID 106971108), the world's largest open chemistry database maintained by the National Library of Medicine (NIH).