C21H29FN2O3 — CID 110201201
(1S,11R)-2-(3-fluoro-4-methoxybenzoyl)-2,9-diazabicyclo[9.4.0]pentadecan-10-one (PubChem CID 110201201) has the molecular formula C21H29FN2O3 and a molecular weight of 376.47 g/mol. Its IUPAC name is (1S,11R)-2-(3-fluoro-4-methoxybenzoyl)-2,9-diazabicyclo[9.4.0]pentadecan-10-one.
| Compound Name | (1S,11R)-2-(3-fluoro-4-methoxybenzoyl)-2,9-diazabicyclo[9.4.0]pentadecan-10-one |
|---|---|
| PubChem CID | 110201201 |
| Molecular Formula | C21H29FN2O3 |
| Molecular Weight | 376.47 g/mol |
| Exact Mass | 376.22 |
| IUPAC Name | (1S,11R)-2-(3-fluoro-4-methoxybenzoyl)-2,9-diazabicyclo[9.4.0]pentadecan-10-one |
| SMILES | COc1ccc(C(=O)N2CCCCCCNC(=O)[C@@H]3CCCC[C@@H]32)cc1F |
| InChI | InChI=1S/C21H29FN2O3/c1-27-19-11-10-15(14-17(19)22)21(26)24-13-7-3-2-6-12-23-20(25)16-8-4-5-9-18(16)24/h10-11,14,16,18H,2-9,12-13H2,1H3,(H,23,25)/t16-,18+/m1/s1 |
| InChIKey | NNFZVFKUTYNBOK-AEFFLSMTSA-N |
| XLogP | 3.53 |
| TPSA | 58.64 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 3 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 27 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 376.47 |
| LogP ≤ 5 | 3.53 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 3 |