C14H11ClFN5O — CID 11537035
5-chloro-15-(2-fluoroethoxy)-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene (PubChem CID 11537035) has the molecular formula C14H11ClFN5O and a molecular weight of 319.73 g/mol. Its IUPAC name is 5-chloro-15-(2-fluoroethoxy)-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene.
| Compound Name | 5-chloro-15-(2-fluoroethoxy)-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene |
|---|---|
| PubChem CID | 11537035 |
| Molecular Formula | C14H11ClFN5O |
| Molecular Weight | 319.73 g/mol |
| Exact Mass | 319.06 |
| IUPAC Name | 5-chloro-15-(2-fluoroethoxy)-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene |
| SMILES | FCCOc1ccc2c(c1)-c1ncnn1Cc1c(Cl)ncn1-2 |
| InChI | InChI=1S/C14H11ClFN5O/c15-13-12-6-21-14(17-7-19-21)10-5-9(22-4-3-16)1-2-11(10)20(12)8-18-13/h1-2,5,7-8H,3-4,6H2 |
| InChIKey | HIAZHPARQOAXPQ-UHFFFAOYSA-N |
| XLogP | 2.49 |
| TPSA | 57.76 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 6 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 22 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 319.73 |
| LogP ≤ 5 | 2.49 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 6 |