C14H10FN5 — CID 11608679
5-ethenyl-15-fluoro-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene (PubChem CID 11608679) has the molecular formula C14H10FN5 and a molecular weight of 267.27 g/mol. Its IUPAC name is 5-ethenyl-15-fluoro-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene.
| Compound Name | 5-ethenyl-15-fluoro-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene |
|---|---|
| PubChem CID | 11608679 |
| Molecular Formula | C14H10FN5 |
| Molecular Weight | 267.27 g/mol |
| Exact Mass | 267.09 |
| IUPAC Name | 5-ethenyl-15-fluoro-2,4,8,9,11-pentazatetracyclo[11.4.0.02,6.08,12]heptadeca-1(13),3,5,9,11,14,16-heptaene |
| SMILES | C=Cc1ncn2c1Cn1ncnc1-c1cc(F)ccc1-2 |
| InChI | InChI=1S/C14H10FN5/c1-2-11-13-6-20-14(16-7-18-20)10-5-9(15)3-4-12(10)19(13)8-17-11/h2-5,7-8H,1,6H2 |
| InChIKey | CPXGLXGVYGJJEV-UHFFFAOYSA-N |
| XLogP | 2.27 |
| TPSA | 48.53 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 267.27 |
| LogP ≤ 5 | 2.27 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 5 |