C16H15BrN2O — CID 117016072
4-(3-bromophenyl)-1,2,3,6-tetrahydro-1,4-benzodiazocin-5-one (PubChem CID 117016072) has the molecular formula C16H15BrN2O and a molecular weight of 331.21 g/mol. Its IUPAC name is 4-(3-bromophenyl)-1,2,3,6-tetrahydro-1,4-benzodiazocin-5-one.
| Compound Name | 4-(3-bromophenyl)-1,2,3,6-tetrahydro-1,4-benzodiazocin-5-one |
|---|---|
| PubChem CID | 117016072 |
| Molecular Formula | C16H15BrN2O |
| Molecular Weight | 331.21 g/mol |
| Exact Mass | 330.04 |
| IUPAC Name | 4-(3-bromophenyl)-1,2,3,6-tetrahydro-1,4-benzodiazocin-5-one |
| SMILES | O=C1Cc2ccccc2NCCN1c1cccc(Br)c1 |
| InChI | InChI=1S/C16H15BrN2O/c17-13-5-3-6-14(11-13)19-9-8-18-15-7-2-1-4-12(15)10-16(19)20/h1-7,11,18H,8-10H2 |
| InChIKey | CUEPSFHXIVJIJT-UHFFFAOYSA-N |
| XLogP | 3.45 |
| TPSA | 32.34 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 2 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 331.21 |
| LogP ≤ 5 | 3.45 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 2 |