C15H24N2O — CID 12914403
(1S,2R,9S,10S)-7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one (PubChem CID 12914403) has the molecular formula C15H24N2O and a molecular weight of 248.37 g/mol. Its IUPAC name is (1S,2R,9S,10S)-7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one.
| Compound Name | (1S,2R,9S,10S)-7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one |
|---|---|
| PubChem CID | 12914403 |
| Molecular Formula | C15H24N2O |
| Molecular Weight | 248.37 g/mol |
| Exact Mass | 248.19 |
| IUPAC Name | (1S,2R,9S,10S)-7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one |
| SMILES | O=C1CCN2C[C@@H]3C[C@@H](CN4CCCC[C@@H]34)[C@H]2C1 |
| InChI | InChI=1S/C15H24N2O/c18-13-4-6-17-9-11-7-12(15(17)8-13)10-16-5-2-1-3-14(11)16/h11-12,14-15H,1-10H2/t11-,12-,14-,15+/m0/s1 |
| InChIKey | RYLSVBDVGRSVHE-NZBPQXDJSA-N |
| XLogP | 1.52 |
| TPSA | 23.55 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 3 |
| Rotatable Bonds | |
| Heavy Atoms | 18 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 248.37 |
| LogP ≤ 5 | 1.52 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 3 |