C17H24FNO — CID 134611799
(1S,9S,13S)-10-(3-fluoropropyl)-1,13-dimethyl-10-azatricyclo[7.3.1.02,7]trideca-2(7),3,5-trien-4-ol (PubChem CID 134611799) has the molecular formula C17H24FNO and a molecular weight of 277.38 g/mol. Its IUPAC name is (1S,9S,13S)-10-(3-fluoropropyl)-1,13-dimethyl-10-azatricyclo[7.3.1.02,7]trideca-2(7),3,5-trien-4-ol.
| Compound Name | (1S,9S,13S)-10-(3-fluoropropyl)-1,13-dimethyl-10-azatricyclo[7.3.1.02,7]trideca-2(7),3,5-trien-4-ol |
|---|---|
| PubChem CID | 134611799 |
| Molecular Formula | C17H24FNO |
| Molecular Weight | 277.38 g/mol |
| Exact Mass | 277.18 |
| IUPAC Name | (1S,9S,13S)-10-(3-fluoropropyl)-1,13-dimethyl-10-azatricyclo[7.3.1.02,7]trideca-2(7),3,5-trien-4-ol |
| SMILES | C[C@@H]1[C@@H]2Cc3ccc(O)cc3[C@@]1(C)CCN2CCCF |
| InChI | InChI=1S/C17H24FNO/c1-12-16-10-13-4-5-14(20)11-15(13)17(12,2)6-9-19(16)8-3-7-18/h4-5,11-12,16,20H,3,6-10H2,1-2H3/t12-,16+,17+/m1/s1 |
| InChIKey | DBYKZHOWVBRCTO-DQYPLSBCSA-N |
| XLogP | 3.28 |
| TPSA | 23.47 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 2 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 277.38 |
| LogP ≤ 5 | 3.28 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 2 |