C10H15BrO4 — CID 134931823
(3aS,4R,5S,7aS)-7-bromo-5-methoxy-2,2-dimethyl-3a,4,5,7a-tetrahydro-1,3-benzodioxol-4-ol (PubChem CID 134931823) has the molecular formula C10H15BrO4 and a molecular weight of 279.13 g/mol. Its IUPAC name is (3aS,4R,5S,7aS)-7-bromo-5-methoxy-2,2-dimethyl-3a,4,5,7a-tetrahydro-1,3-benzodioxol-4-ol.
| Compound Name | (3aS,4R,5S,7aS)-7-bromo-5-methoxy-2,2-dimethyl-3a,4,5,7a-tetrahydro-1,3-benzodioxol-4-ol |
|---|---|
| PubChem CID | 134931823 |
| Molecular Formula | C10H15BrO4 |
| Molecular Weight | 279.13 g/mol |
| Exact Mass | 278.02 |
| IUPAC Name | (3aS,4R,5S,7aS)-7-bromo-5-methoxy-2,2-dimethyl-3a,4,5,7a-tetrahydro-1,3-benzodioxol-4-ol |
| SMILES | CO[C@H]1C=C(Br)[C@H]2OC(C)(C)O[C@H]2[C@@H]1O |
| InChI | InChI=1S/C10H15BrO4/c1-10(2)14-8-5(11)4-6(13-3)7(12)9(8)15-10/h4,6-9,12H,1-3H3/t6-,7+,8+,9-/m0/s1 |
| InChIKey | QIEYOGFTPWVLTR-KDXUFGMBSA-N |
| XLogP | 1.17 |
| TPSA | 47.92 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 15 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 279.13 |
| LogP ≤ 5 | 1.17 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 4 |