C10H6FN5O — CID 135623219
6-fluoro-3-(2H-tetrazol-5-yl)-1H-quinolin-4-one (PubChem CID 135623219) has the molecular formula C10H6FN5O and a molecular weight of 231.19 g/mol. Its IUPAC name is 6-fluoro-3-(2H-tetrazol-5-yl)-1H-quinolin-4-one.
| Compound Name | 6-fluoro-3-(2H-tetrazol-5-yl)-1H-quinolin-4-one |
|---|---|
| PubChem CID | 135623219 |
| Molecular Formula | C10H6FN5O |
| Molecular Weight | 231.19 g/mol |
| Exact Mass | 231.06 |
| IUPAC Name | 6-fluoro-3-(2H-tetrazol-5-yl)-1H-quinolin-4-one |
| SMILES | O=c1c(-c2nn[nH]n2)c[nH]c2ccc(F)cc12 |
| InChI | InChI=1S/C10H6FN5O/c11-5-1-2-8-6(3-5)9(17)7(4-12-8)10-13-15-16-14-10/h1-4H,(H,12,17)(H,13,14,15,16) |
| InChIKey | FKDXLSINWVFXIC-UHFFFAOYSA-N |
| XLogP | 0.85 |
| TPSA | 87.32 Ų |
| H-Bond Donors | 2 |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 17 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 231.19 |
| LogP ≤ 5 | 0.85 |
| H-Bond Donors ≤ 5 | 2 |
| H-Bond Acceptors ≤ 10 | 4 |