C15H15FN4O — CID 137083667
11-fluoro-3-propyl-3,6,7,16-tetrazatetracyclo[11.2.1.05,15.09,14]hexadeca-5(15),6,9(14),10,12-pentaen-8-one (PubChem CID 137083667) has the molecular formula C15H15FN4O and a molecular weight of 286.31 g/mol. Its IUPAC name is 11-fluoro-3-propyl-3,6,7,16-tetrazatetracyclo[11.2.1.05,15.09,14]hexadeca-5(15),6,9(14),10,12-pentaen-8-one.
| Compound Name | 11-fluoro-3-propyl-3,6,7,16-tetrazatetracyclo[11.2.1.05,15.09,14]hexadeca-5(15),6,9(14),10,12-pentaen-8-one |
|---|---|
| PubChem CID | 137083667 |
| Molecular Formula | C15H15FN4O |
| Molecular Weight | 286.31 g/mol |
| Exact Mass | 286.12 |
| IUPAC Name | 11-fluoro-3-propyl-3,6,7,16-tetrazatetracyclo[11.2.1.05,15.09,14]hexadeca-5(15),6,9(14),10,12-pentaen-8-one |
| SMILES | CCCN1Cc2nnc(=O)c3cc(F)cc4c3c2C(C1)N4 |
| InChI | InChI=1S/C15H15FN4O/c1-2-3-20-6-11-14-12(7-20)18-19-15(21)9-4-8(16)5-10(17-11)13(9)14/h4-5,11,17H,2-3,6-7H2,1H3 |
| InChIKey | KSSQXRJSAGCXMH-UHFFFAOYSA-N |
| XLogP | 1.82 |
| TPSA | 58.12 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 21 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 286.31 |
| LogP ≤ 5 | 1.82 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 5 |