C11H15FN2 — CID 144891268
(1E,3E,5Z,7Z)-4-N-(2-fluoroethyl)-4-N-methylcycloocta-1,3,5,7-tetraene-1,4-diamine (PubChem CID 144891268) has the molecular formula C11H15FN2 and a molecular weight of 194.25 g/mol. Its IUPAC name is (1E,3E,5Z,7Z)-4-N-(2-fluoroethyl)-4-N-methylcycloocta-1,3,5,7-tetraene-1,4-diamine.
| Compound Name | (1E,3E,5Z,7Z)-4-N-(2-fluoroethyl)-4-N-methylcycloocta-1,3,5,7-tetraene-1,4-diamine |
|---|---|
| PubChem CID | 144891268 |
| Molecular Formula | C11H15FN2 |
| Molecular Weight | 194.25 g/mol |
| Exact Mass | 194.12 |
| IUPAC Name | (1E,3E,5Z,7Z)-4-N-(2-fluoroethyl)-4-N-methylcycloocta-1,3,5,7-tetraene-1,4-diamine |
| SMILES | CN(CCF)C1=C/C=C(N)\C=C/C=C\1 |
| InChI | InChI=1S/C11H15FN2/c1-14(9-8-12)11-5-3-2-4-10(13)6-7-11/h2-7H,8-9,13H2,1H3/b3-2-,4-2-,5-3-,7-6-,10-4+,10-6+,11-5+,11-7+ |
| InChIKey | FGHNOLFOJSBILO-TZJFUFHCSA-N |
| XLogP | 1.74 |
| TPSA | 29.26 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 2 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 14 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 194.25 |
| LogP ≤ 5 | 1.74 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 2 |