C18H15FN4O — CID 153452502
1-(5-fluoro-3,4,5,13-tetrazatetracyclo[13.4.0.02,6.07,12]nonadeca-1(19),2(6),3,7,9,11,15,17-octaen-13-yl)propan-1-one (PubChem CID 153452502) has the molecular formula C18H15FN4O and a molecular weight of 322.34 g/mol. Its IUPAC name is 1-(5-fluoro-3,4,5,13-tetrazatetracyclo[13.4.0.02,6.07,12]nonadeca-1(19),2(6),3,7,9,11,15,17-octaen-13-yl)propan-1-one.
| Compound Name | 1-(5-fluoro-3,4,5,13-tetrazatetracyclo[13.4.0.02,6.07,12]nonadeca-1(19),2(6),3,7,9,11,15,17-octaen-13-yl)propan-1-one |
|---|---|
| PubChem CID | 153452502 |
| Molecular Formula | C18H15FN4O |
| Molecular Weight | 322.34 g/mol |
| Exact Mass | 322.12 |
| IUPAC Name | 1-(5-fluoro-3,4,5,13-tetrazatetracyclo[13.4.0.02,6.07,12]nonadeca-1(19),2(6),3,7,9,11,15,17-octaen-13-yl)propan-1-one |
| SMILES | CCC(=O)N1Cc2ccccc2-c2nnn(F)c2-c2ccccc21 |
| InChI | InChI=1S/C18H15FN4O/c1-2-16(24)22-11-12-7-3-4-8-13(12)17-18(23(19)21-20-17)14-9-5-6-10-15(14)22/h3-10H,2,11H2,1H3 |
| InChIKey | OJBALMOOALGERW-UHFFFAOYSA-N |
| XLogP | 3.60 |
| TPSA | 51.02 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 24 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 322.34 |
| LogP ≤ 5 | 3.60 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 4 |