C13H10ClN3O3S — CID 169149998
2-(4-chloro-12-cyclopropyl-9-oxo-3-thia-1,10,11-triazatricyclo[6.4.0.02,6]dodeca-2(6),4,7,11-tetraen-10-yl)acetic acid (PubChem CID 169149998) has the molecular formula C13H10ClN3O3S and a molecular weight of 323.76 g/mol. Its IUPAC name is 2-(4-chloro-12-cyclopropyl-9-oxo-3-thia-1,10,11-triazatricyclo[6.4.0.02,6]dodeca-2(6),4,7,11-tetraen-10-yl)acetic acid.
| Compound Name | 2-(4-chloro-12-cyclopropyl-9-oxo-3-thia-1,10,11-triazatricyclo[6.4.0.02,6]dodeca-2(6),4,7,11-tetraen-10-yl)acetic acid |
|---|---|
| PubChem CID | 169149998 |
| Molecular Formula | C13H10ClN3O3S |
| Molecular Weight | 323.76 g/mol |
| Exact Mass | 323.01 |
| IUPAC Name | 2-(4-chloro-12-cyclopropyl-9-oxo-3-thia-1,10,11-triazatricyclo[6.4.0.02,6]dodeca-2(6),4,7,11-tetraen-10-yl)acetic acid |
| SMILES | O=C(O)Cn1nc(C2CC2)n2c(cc3cc(Cl)sc32)c1=O |
| InChI | InChI=1S/C13H10ClN3O3S/c14-9-4-7-3-8-12(20)16(5-10(18)19)15-11(6-1-2-6)17(8)13(7)21-9/h3-4,6H,1-2,5H2,(H,18,19) |
| InChIKey | VMUUPMIXCCNKBI-UHFFFAOYSA-N |
| XLogP | 2.33 |
| TPSA | 76.60 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 6 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 21 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 323.76 |
| LogP ≤ 5 | 2.33 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 6 |