C19H11FN4O — CID 30466223
5-(2-fluorophenyl)-1,5,9,11-tetrazatetracyclo[8.7.0.02,7.012,17]heptadeca-2(7),3,8,10,12,14,16-heptaen-6-one (PubChem CID 30466223) has the molecular formula C19H11FN4O and a molecular weight of 330.32 g/mol. Its IUPAC name is 5-(2-fluorophenyl)-1,5,9,11-tetrazatetracyclo[8.7.0.02,7.012,17]heptadeca-2(7),3,8,10,12,14,16-heptaen-6-one.
| Compound Name | 5-(2-fluorophenyl)-1,5,9,11-tetrazatetracyclo[8.7.0.02,7.012,17]heptadeca-2(7),3,8,10,12,14,16-heptaen-6-one |
|---|---|
| PubChem CID | 30466223 |
| Molecular Formula | C19H11FN4O |
| Molecular Weight | 330.32 g/mol |
| Exact Mass | 330.09 |
| IUPAC Name | 5-(2-fluorophenyl)-1,5,9,11-tetrazatetracyclo[8.7.0.02,7.012,17]heptadeca-2(7),3,8,10,12,14,16-heptaen-6-one |
| SMILES | O=c1c2cnc3nc4ccccc4n3c2ccn1-c1ccccc1F |
| InChI | InChI=1S/C19H11FN4O/c20-13-5-1-3-7-16(13)23-10-9-15-12(18(23)25)11-21-19-22-14-6-2-4-8-17(14)24(15)19/h1-11H |
| InChIKey | WCIUQPJMUDRTFC-UHFFFAOYSA-N |
| XLogP | 3.33 |
| TPSA | 52.19 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 25 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 330.32 |
| LogP ≤ 5 | 3.33 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 5 |