C20H14FN3O — CID 46224796
2-fluoro-4-(8,12,14-triazatetracyclo[8.6.1.02,7.013,17]heptadeca-1(17),2,4,6,10,13,15-heptaen-9-yl)phenol (PubChem CID 46224796) has the molecular formula C20H14FN3O and a molecular weight of 331.35 g/mol. Its IUPAC name is 2-fluoro-4-(8,12,14-triazatetracyclo[8.6.1.02,7.013,17]heptadeca-1(17),2,4,6,10,13,15-heptaen-9-yl)phenol.
| Compound Name | 2-fluoro-4-(8,12,14-triazatetracyclo[8.6.1.02,7.013,17]heptadeca-1(17),2,4,6,10,13,15-heptaen-9-yl)phenol |
|---|---|
| PubChem CID | 46224796 |
| Molecular Formula | C20H14FN3O |
| Molecular Weight | 331.35 g/mol |
| Exact Mass | 331.11 |
| IUPAC Name | 2-fluoro-4-(8,12,14-triazatetracyclo[8.6.1.02,7.013,17]heptadeca-1(17),2,4,6,10,13,15-heptaen-9-yl)phenol |
| SMILES | Oc1ccc(C2Nc3ccccc3-c3ccnc4[nH]cc2c34)cc1F |
| InChI | InChI=1S/C20H14FN3O/c21-15-9-11(5-6-17(15)25)19-14-10-23-20-18(14)13(7-8-22-20)12-3-1-2-4-16(12)24-19/h1-10,19,24-25H,(H,22,23) |
| InChIKey | XZBDMMYLOSUXDO-UHFFFAOYSA-N |
| XLogP | 4.59 |
| TPSA | 60.94 Ų |
| H-Bond Donors | 3 |
| H-Bond Acceptors | 3 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 25 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 331.35 |
| LogP ≤ 5 | 4.59 |
| H-Bond Donors ≤ 5 | 3 |
| H-Bond Acceptors ≤ 10 | 3 |