C17H15ClN4O2 — CID 53184100
11-acetyl-5-(2-chlorophenyl)-2,6,7,11-tetrazatricyclo[7.4.0.03,7]trideca-1(9),2,4-trien-8-one (PubChem CID 53184100) has the molecular formula C17H15ClN4O2 and a molecular weight of 342.79 g/mol. Its IUPAC name is 11-acetyl-5-(2-chlorophenyl)-2,6,7,11-tetrazatricyclo[7.4.0.03,7]trideca-1(9),2,4-trien-8-one.
| Compound Name | 11-acetyl-5-(2-chlorophenyl)-2,6,7,11-tetrazatricyclo[7.4.0.03,7]trideca-1(9),2,4-trien-8-one |
|---|---|
| PubChem CID | 53184100 |
| Molecular Formula | C17H15ClN4O2 |
| Molecular Weight | 342.79 g/mol |
| Exact Mass | 342.09 |
| IUPAC Name | 11-acetyl-5-(2-chlorophenyl)-2,6,7,11-tetrazatricyclo[7.4.0.03,7]trideca-1(9),2,4-trien-8-one |
| SMILES | CC(=O)N1CCc2nc3cc(-c4ccccc4Cl)[nH]n3c(=O)c2C1 |
| InChI | InChI=1S/C17H15ClN4O2/c1-10(23)21-7-6-14-12(9-21)17(24)22-16(19-14)8-15(20-22)11-4-2-3-5-13(11)18/h2-5,8,20H,6-7,9H2,1H3 |
| InChIKey | DTLONGWUSIEXCB-UHFFFAOYSA-N |
| XLogP | 2.25 |
| TPSA | 70.47 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 24 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 342.79 |
| LogP ≤ 5 | 2.25 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 4 |