C19H15BrN4O — CID 56588987
4-bromo-16-phenyl-10,13,14,15-tetrazatetracyclo[8.7.0.02,7.013,17]heptadeca-2(7),3,5,14,16-pentaen-11-one (PubChem CID 56588987) has the molecular formula C19H15BrN4O and a molecular weight of 395.26 g/mol. Its IUPAC name is 4-bromo-16-phenyl-10,13,14,15-tetrazatetracyclo[8.7.0.02,7.013,17]heptadeca-2(7),3,5,14,16-pentaen-11-one.
| Compound Name | 4-bromo-16-phenyl-10,13,14,15-tetrazatetracyclo[8.7.0.02,7.013,17]heptadeca-2(7),3,5,14,16-pentaen-11-one |
|---|---|
| PubChem CID | 56588987 |
| Molecular Formula | C19H15BrN4O |
| Molecular Weight | 395.26 g/mol |
| Exact Mass | 394.04 |
| IUPAC Name | 4-bromo-16-phenyl-10,13,14,15-tetrazatetracyclo[8.7.0.02,7.013,17]heptadeca-2(7),3,5,14,16-pentaen-11-one |
| SMILES | O=C1Cn2nnc(-c3ccccc3)c2C2c3cc(Br)ccc3CCN12 |
| InChI | InChI=1S/C19H15BrN4O/c20-14-7-6-12-8-9-23-16(25)11-24-19(18(23)15(12)10-14)17(21-22-24)13-4-2-1-3-5-13/h1-7,10,18H,8-9,11H2 |
| InChIKey | IWTJCWKJWKPYBQ-UHFFFAOYSA-N |
| XLogP | 3.20 |
| TPSA | 51.02 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 25 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 395.26 |
| LogP ≤ 5 | 3.20 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 4 |