C15H10FNO3 — CID 656954
7-ethenyl-2-(3-fluoro-4-hydroxyphenyl)-1,3-benzoxazol-5-ol (PubChem CID 656954) has the molecular formula C15H10FNO3 and a molecular weight of 271.25 g/mol. Its IUPAC name is 7-ethenyl-2-(3-fluoro-4-hydroxyphenyl)-1,3-benzoxazol-5-ol.
| Compound Name | 7-ethenyl-2-(3-fluoro-4-hydroxyphenyl)-1,3-benzoxazol-5-ol |
|---|---|
| PubChem CID | 656954 |
| Molecular Formula | C15H10FNO3 |
| Molecular Weight | 271.25 g/mol |
| Exact Mass | 271.06 |
| IUPAC Name | 7-ethenyl-2-(3-fluoro-4-hydroxyphenyl)-1,3-benzoxazol-5-ol |
| SMILES | C=Cc1cc(O)cc2nc(-c3ccc(O)c(F)c3)oc12 |
| InChI | InChI=1S/C15H10FNO3/c1-2-8-5-10(18)7-12-14(8)20-15(17-12)9-3-4-13(19)11(16)6-9/h2-7,18-19H,1H2 |
| InChIKey | MQIMZDXIAHJKQP-UHFFFAOYSA-N |
| XLogP | 3.69 |
| TPSA | 66.49 Ų |
| H-Bond Donors | 2 |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 271.25 |
| LogP ≤ 5 | 3.69 |
| H-Bond Donors ≤ 5 | 2 |
| H-Bond Acceptors ≤ 10 | 4 |