4-(1-fluoroethenyl)-1,3-dioxolan-2-one

C5H5FO3 — CID 69479594

IUPAC4-(1-fluoroethenyl)-1,3-dioxolan-2-one
SMILESC=C(F)C1COC(=O)O1
InChIInChI=1S/C5H5FO3/c1-3(6)4-2-8-5(7)9-4/h4H,1-2H2
InChIKeyYPDFZOWNOFYVBQ-UHFFFAOYSA-N
MW132.09 g/mol
LogP1.00
Rot. Bonds1

About 4-(1-fluoroethenyl)-1,3-dioxolan-2-one

4-(1-fluoroethenyl)-1,3-dioxolan-2-one (PubChem CID 69479594) has the molecular formula C5H5FO3 and a molecular weight of 132.09 g/mol. Its IUPAC name is 4-(1-fluoroethenyl)-1,3-dioxolan-2-one.

Molecular Properties

Compound Name4-(1-fluoroethenyl)-1,3-dioxolan-2-one
PubChem CID69479594
Molecular FormulaC5H5FO3
Molecular Weight132.09 g/mol
Exact Mass132.02
IUPAC Name4-(1-fluoroethenyl)-1,3-dioxolan-2-one
SMILESC=C(F)C1COC(=O)O1
InChIInChI=1S/C5H5FO3/c1-3(6)4-2-8-5(7)9-4/h4H,1-2H2
InChIKeyYPDFZOWNOFYVBQ-UHFFFAOYSA-N
XLogP1.00
TPSA35.53 Ų
H-Bond Donors
H-Bond Acceptors3
Rotatable Bonds1
Heavy Atoms9
Complexity—

Lipinski Rule of Five

Passes Rule of Five

RuleValue
MW ≤ 500132.09
LogP ≤ 51.00
H-Bond Donors ≤ 50
H-Bond Acceptors ≤ 103

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Frequently Asked Questions

What is the IUPAC name of 4-(1-fluoroethenyl)-1,3-dioxolan-2-one?
The IUPAC name of 4-(1-fluoroethenyl)-1,3-dioxolan-2-one (CID 69479594) is 4-(1-fluoroethenyl)-1,3-dioxolan-2-one.
What is the SMILES notation for 4-(1-fluoroethenyl)-1,3-dioxolan-2-one?
The canonical SMILES for 4-(1-fluoroethenyl)-1,3-dioxolan-2-one is C=C(F)C1COC(=O)O1.
What is the InChIKey of 4-(1-fluoroethenyl)-1,3-dioxolan-2-one?
The InChIKey is YPDFZOWNOFYVBQ-UHFFFAOYSA-N. The full InChI is InChI=1S/C5H5FO3/c1-3(6)4-2-8-5(7)9-4/h4H,1-2H2.
What are the key properties of 4-(1-fluoroethenyl)-1,3-dioxolan-2-one?
4-(1-fluoroethenyl)-1,3-dioxolan-2-one has a molecular weight of 132.09 g/mol, XLogP of 1.00, 1 rotatable bonds, 0 hydrogen bond donors, and 3 hydrogen bond acceptors.
Where does this data come from?
All data for 4-(1-fluoroethenyl)-1,3-dioxolan-2-one is sourced from PubChem (CID 69479594), the world's largest open chemistry database maintained by the National Library of Medicine (NIH).