C19H14F2N2O — CID 71731594
4,6-bis(4-fluorophenyl)-1,2,4,5-tetrahydroindazol-3-one (PubChem CID 71731594) has the molecular formula C19H14F2N2O and a molecular weight of 324.33 g/mol. Its IUPAC name is 4,6-bis(4-fluorophenyl)-1,2,4,5-tetrahydroindazol-3-one.
| Compound Name | 4,6-bis(4-fluorophenyl)-1,2,4,5-tetrahydroindazol-3-one |
|---|---|
| PubChem CID | 71731594 |
| Molecular Formula | C19H14F2N2O |
| Molecular Weight | 324.33 g/mol |
| Exact Mass | 324.11 |
| IUPAC Name | 4,6-bis(4-fluorophenyl)-1,2,4,5-tetrahydroindazol-3-one |
| SMILES | O=c1[nH][nH]c2c1C(c1ccc(F)cc1)CC(c1ccc(F)cc1)=C2 |
| InChI | InChI=1S/C19H14F2N2O/c20-14-5-1-11(2-6-14)13-9-16(12-3-7-15(21)8-4-12)18-17(10-13)22-23-19(18)24/h1-8,10,16H,9H2,(H2,22,23,24) |
| InChIKey | QSTVAPGHPGBYLK-UHFFFAOYSA-N |
| XLogP | 4.06 |
| TPSA | 48.65 Ų |
| H-Bond Donors | 2 |
| H-Bond Acceptors | 1 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 24 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 324.33 |
| LogP ≤ 5 | 4.06 |
| H-Bond Donors ≤ 5 | 2 |
| H-Bond Acceptors ≤ 10 | 1 |