C14H15FN4O3 — CID 91910584
7-(3-fluoro-4-methoxybenzoyl)-5,6,8,9-tetrahydro-2H-[1,2,4]triazolo[4,3-d][1,4]diazepin-3-one (PubChem CID 91910584) has the molecular formula C14H15FN4O3 and a molecular weight of 306.30 g/mol. Its IUPAC name is 7-(3-fluoro-4-methoxybenzoyl)-5,6,8,9-tetrahydro-2H-[1,2,4]triazolo[4,3-d][1,4]diazepin-3-one.
| Compound Name | 7-(3-fluoro-4-methoxybenzoyl)-5,6,8,9-tetrahydro-2H-[1,2,4]triazolo[4,3-d][1,4]diazepin-3-one |
|---|---|
| PubChem CID | 91910584 |
| Molecular Formula | C14H15FN4O3 |
| Molecular Weight | 306.30 g/mol |
| Exact Mass | 306.11 |
| IUPAC Name | 7-(3-fluoro-4-methoxybenzoyl)-5,6,8,9-tetrahydro-2H-[1,2,4]triazolo[4,3-d][1,4]diazepin-3-one |
| SMILES | COc1ccc(C(=O)N2CCc3n[nH]c(=O)n3CC2)cc1F |
| InChI | InChI=1S/C14H15FN4O3/c1-22-11-3-2-9(8-10(11)15)13(20)18-5-4-12-16-17-14(21)19(12)7-6-18/h2-3,8H,4-7H2,1H3,(H,17,21) |
| InChIKey | ZBOOMLOCTOFVET-UHFFFAOYSA-N |
| XLogP | 0.42 |
| TPSA | 80.22 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 22 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 306.30 |
| LogP ≤ 5 | 0.42 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 5 |