C15H24ClN3O — CID 114438468
4-chloro-5-(1-cyclopentylethylamino)-2-(2-methylpropyl)pyridazin-3-one (PubChem CID 114438468) has the molecular formula C15H24ClN3O and a molecular weight of 297.83 g/mol. Its IUPAC name is 4-chloro-5-(1-cyclopentylethylamino)-2-(2-methylpropyl)pyridazin-3-one.
| Compound Name | 4-chloro-5-(1-cyclopentylethylamino)-2-(2-methylpropyl)pyridazin-3-one |
|---|---|
| PubChem CID | 114438468 |
| Molecular Formula | C15H24ClN3O |
| Molecular Weight | 297.83 g/mol |
| Exact Mass | 297.16 |
| IUPAC Name | 4-chloro-5-(1-cyclopentylethylamino)-2-(2-methylpropyl)pyridazin-3-one |
| SMILES | CC(C)Cn1ncc(NC(C)C2CCCC2)c(Cl)c1=O |
| InChI | InChI=1S/C15H24ClN3O/c1-10(2)9-19-15(20)14(16)13(8-17-19)18-11(3)12-6-4-5-7-12/h8,10-12,18H,4-7,9H2,1-3H3 |
| InChIKey | BYZAEMMFPIDMBL-UHFFFAOYSA-N |
| XLogP | 3.54 |
| TPSA | 46.92 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 4 |
| Rotatable Bonds | 5 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 297.83 |
| LogP ≤ 5 | 3.54 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 4 |