C14H15FN4O — CID 157041311
(1R,5R,6S)-5-[4-(3-fluorophenyl)triazol-1-yl]-3-methyl-7-oxa-3-azabicyclo[4.1.0]heptane (PubChem CID 157041311) has the molecular formula C14H15FN4O and a molecular weight of 274.30 g/mol. Its IUPAC name is (1R,5R,6S)-5-[4-(3-fluorophenyl)triazol-1-yl]-3-methyl-7-oxa-3-azabicyclo[4.1.0]heptane.
| Compound Name | (1R,5R,6S)-5-[4-(3-fluorophenyl)triazol-1-yl]-3-methyl-7-oxa-3-azabicyclo[4.1.0]heptane |
|---|---|
| PubChem CID | 157041311 |
| Molecular Formula | C14H15FN4O |
| Molecular Weight | 274.30 g/mol |
| Exact Mass | 274.12 |
| IUPAC Name | (1R,5R,6S)-5-[4-(3-fluorophenyl)triazol-1-yl]-3-methyl-7-oxa-3-azabicyclo[4.1.0]heptane |
| SMILES | CN1C[C@@H](n2cc(-c3cccc(F)c3)nn2)[C@@H]2O[C@@H]2C1 |
| InChI | InChI=1S/C14H15FN4O/c1-18-7-12(14-13(8-18)20-14)19-6-11(16-17-19)9-3-2-4-10(15)5-9/h2-6,12-14H,7-8H2,1H3/t12-,13-,14+/m1/s1 |
| InChIKey | LGHHAUZMGDFOAB-MCIONIFRSA-N |
| XLogP | 1.34 |
| TPSA | 46.48 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 2 |
| Heavy Atoms | 20 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 274.30 |
| LogP ≤ 5 | 1.34 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 5 |
| Structural Alerts | {'alert_name': 'Three-membered_heterocycle', 'substructure': 'N/A'} |
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