C14H15FN2O — CID 66489189
6-(4-fluorophenyl)-3-methyl-4,5,6,7-tetrahydro-2H-indazol-4-ol (PubChem CID 66489189) has the molecular formula C14H15FN2O and a molecular weight of 246.28 g/mol. Its IUPAC name is 6-(4-fluorophenyl)-3-methyl-4,5,6,7-tetrahydro-2H-indazol-4-ol.
| Compound Name | 6-(4-fluorophenyl)-3-methyl-4,5,6,7-tetrahydro-2H-indazol-4-ol |
|---|---|
| PubChem CID | 66489189 |
| Molecular Formula | C14H15FN2O |
| Molecular Weight | 246.28 g/mol |
| Exact Mass | 246.12 |
| IUPAC Name | 6-(4-fluorophenyl)-3-methyl-4,5,6,7-tetrahydro-2H-indazol-4-ol |
| SMILES | Cc1[nH]nc2c1C(O)CC(c1ccc(F)cc1)C2 |
| InChI | InChI=1S/C14H15FN2O/c1-8-14-12(17-16-8)6-10(7-13(14)18)9-2-4-11(15)5-3-9/h2-5,10,13,18H,6-7H2,1H3,(H,16,17) |
| InChIKey | CRLNGJPDCGXYIJ-UHFFFAOYSA-N |
| XLogP | 2.62 |
| TPSA | 48.91 Ų |
| H-Bond Donors | 2 |
| H-Bond Acceptors | 2 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 18 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 246.28 |
| LogP ≤ 5 | 2.62 |
| H-Bond Donors ≤ 5 | 2 |
| H-Bond Acceptors ≤ 10 | 2 |