C14H16FN3O — CID 102883587
5-cyclopentyl-3-(2-fluoro-4-methoxyphenyl)-1H-1,2,4-triazole (PubChem CID 102883587) has the molecular formula C14H16FN3O and a molecular weight of 261.30 g/mol. Its IUPAC name is 5-cyclopentyl-3-(2-fluoro-4-methoxyphenyl)-1H-1,2,4-triazole.
| Compound Name | 5-cyclopentyl-3-(2-fluoro-4-methoxyphenyl)-1H-1,2,4-triazole |
|---|---|
| PubChem CID | 102883587 |
| Molecular Formula | C14H16FN3O |
| Molecular Weight | 261.30 g/mol |
| Exact Mass | 261.13 |
| IUPAC Name | 5-cyclopentyl-3-(2-fluoro-4-methoxyphenyl)-1H-1,2,4-triazole |
| SMILES | COc1ccc(-c2n[nH]c(C3CCCC3)n2)c(F)c1 |
| InChI | InChI=1S/C14H16FN3O/c1-19-10-6-7-11(12(15)8-10)14-16-13(17-18-14)9-4-2-3-5-9/h6-9H,2-5H2,1H3,(H,16,17,18) |
| InChIKey | MSQKDFAMOBMYFE-UHFFFAOYSA-N |
| XLogP | 3.28 |
| TPSA | 50.80 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 3 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 19 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 261.30 |
| LogP ≤ 5 | 3.28 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 3 |