C10H15ClN4O — CID 114444067
4-(2-aminoethylamino)-5-chloro-2-(cyclopropylmethyl)pyridazin-3-one (PubChem CID 114444067) has the molecular formula C10H15ClN4O and a molecular weight of 242.71 g/mol. Its IUPAC name is 4-(2-aminoethylamino)-5-chloro-2-(cyclopropylmethyl)pyridazin-3-one.
| Compound Name | 4-(2-aminoethylamino)-5-chloro-2-(cyclopropylmethyl)pyridazin-3-one |
|---|---|
| PubChem CID | 114444067 |
| Molecular Formula | C10H15ClN4O |
| Molecular Weight | 242.71 g/mol |
| Exact Mass | 242.09 |
| IUPAC Name | 4-(2-aminoethylamino)-5-chloro-2-(cyclopropylmethyl)pyridazin-3-one |
| SMILES | NCCNc1c(Cl)cnn(CC2CC2)c1=O |
| InChI | InChI=1S/C10H15ClN4O/c11-8-5-14-15(6-7-1-2-7)10(16)9(8)13-4-3-12/h5,7,13H,1-4,6,12H2 |
| InChIKey | NCJFTCKNUREOMC-UHFFFAOYSA-N |
| XLogP | 0.68 |
| TPSA | 72.94 Ų |
| H-Bond Donors | 2 |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 5 |
| Heavy Atoms | 16 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 242.71 |
| LogP ≤ 5 | 0.68 |
| H-Bond Donors ≤ 5 | 2 |
| H-Bond Acceptors ≤ 10 | 5 |