C15H24N2O — CID 12914402
7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one (PubChem CID 12914402) has the molecular formula C15H24N2O and a molecular weight of 248.37 g/mol. Its IUPAC name is 7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one.
| Compound Name | 7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one |
|---|---|
| PubChem CID | 12914402 |
| Molecular Formula | C15H24N2O |
| Molecular Weight | 248.37 g/mol |
| Exact Mass | 248.19 |
| IUPAC Name | 7,15-diazatetracyclo[7.7.1.02,7.010,15]heptadecan-4-one |
| SMILES | O=C1CCN2CC3CC(CN4CCCCC34)C2C1 |
| InChI | InChI=1S/C15H24N2O/c18-13-4-6-17-9-11-7-12(15(17)8-13)10-16-5-2-1-3-14(11)16/h11-12,14-15H,1-10H2 |
| InChIKey | RYLSVBDVGRSVHE-UHFFFAOYSA-N |
| XLogP | 1.52 |
| TPSA | 23.55 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 3 |
| Rotatable Bonds | |
| Heavy Atoms | 18 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 248.37 |
| LogP ≤ 5 | 1.52 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 3 |