C10H3ClFN5O4S — CID 139461492
4-(3-chloro-4-fluorophenyl)-3-(4-nitro-1,2,5-thiadiazol-3-yl)-1,2,4-oxadiazol-5-one (PubChem CID 139461492) has the molecular formula C10H3ClFN5O4S and a molecular weight of 343.68 g/mol. Its IUPAC name is 4-(3-chloro-4-fluorophenyl)-3-(4-nitro-1,2,5-thiadiazol-3-yl)-1,2,4-oxadiazol-5-one.
| Compound Name | 4-(3-chloro-4-fluorophenyl)-3-(4-nitro-1,2,5-thiadiazol-3-yl)-1,2,4-oxadiazol-5-one |
|---|---|
| PubChem CID | 139461492 |
| Molecular Formula | C10H3ClFN5O4S |
| Molecular Weight | 343.68 g/mol |
| Exact Mass | 342.96 |
| IUPAC Name | 4-(3-chloro-4-fluorophenyl)-3-(4-nitro-1,2,5-thiadiazol-3-yl)-1,2,4-oxadiazol-5-one |
| SMILES | O=c1onc(-c2nsnc2[N+](=O)[O-])n1-c1ccc(F)c(Cl)c1 |
| InChI | InChI=1S/C10H3ClFN5O4S/c11-5-3-4(1-2-6(5)12)16-8(13-21-10(16)18)7-9(17(19)20)15-22-14-7/h1-3H |
| InChIKey | XSXDIBPZPFXNNH-UHFFFAOYSA-N |
| XLogP | 2.04 |
| TPSA | 116.95 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 9 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 22 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 343.68 |
| LogP ≤ 5 | 2.04 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 9 |
| Structural Alerts | {'alert_name': 'nitro_group', 'substructure': 'N/A'}, {'alert_name': 'Oxygen-nitrogen_single_bond', 'substructure': 'N/A'} |
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