C17H9ClN4OS — CID 16659643
13-(4-chlorophenyl)-10-thia-3,8,13,15-tetrazatetracyclo[7.7.0.02,6.011,16]hexadeca-1,4,6,8,11(16),14-hexaen-12-one (PubChem CID 16659643) has the molecular formula C17H9ClN4OS and a molecular weight of 352.81 g/mol. Its IUPAC name is 13-(4-chlorophenyl)-10-thia-3,8,13,15-tetrazatetracyclo[7.7.0.02,6.011,16]hexadeca-1,4,6,8,11(16),14-hexaen-12-one.
| Compound Name | 13-(4-chlorophenyl)-10-thia-3,8,13,15-tetrazatetracyclo[7.7.0.02,6.011,16]hexadeca-1,4,6,8,11(16),14-hexaen-12-one |
|---|---|
| PubChem CID | 16659643 |
| Molecular Formula | C17H9ClN4OS |
| Molecular Weight | 352.81 g/mol |
| Exact Mass | 352.02 |
| IUPAC Name | 13-(4-chlorophenyl)-10-thia-3,8,13,15-tetrazatetracyclo[7.7.0.02,6.011,16]hexadeca-1,4,6,8,11(16),14-hexaen-12-one |
| SMILES | O=c1c2sc3ncc4cc[nH]c4c3c2ncn1-c1ccc(Cl)cc1 |
| InChI | InChI=1S/C17H9ClN4OS/c18-10-1-3-11(4-2-10)22-8-21-14-12-13-9(5-6-19-13)7-20-16(12)24-15(14)17(22)23/h1-8,19H |
| InChIKey | GOYJLRKZEAXDRY-UHFFFAOYSA-N |
| XLogP | 4.13 |
| TPSA | 63.57 Ų |
| H-Bond Donors | 1 |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 24 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 352.81 |
| LogP ≤ 5 | 4.13 |
| H-Bond Donors ≤ 5 | 1 |
| H-Bond Acceptors ≤ 10 | 5 |