C15H17ClN4O — CID 110173700
7-chloro-12-methoxy-5-methyl-3-(2-methylpropyl)-2,4,8,13-tetrazatricyclo[7.4.0.02,6]trideca-1(9),3,5,7,10,12-hexaene (PubChem CID 110173700) has the molecular formula C15H17ClN4O and a molecular weight of 304.78 g/mol. Its IUPAC name is 7-chloro-12-methoxy-5-methyl-3-(2-methylpropyl)-2,4,8,13-tetrazatricyclo[7.4.0.02,6]trideca-1(9),3,5,7,10,12-hexaene.
| Compound Name | 7-chloro-12-methoxy-5-methyl-3-(2-methylpropyl)-2,4,8,13-tetrazatricyclo[7.4.0.02,6]trideca-1(9),3,5,7,10,12-hexaene |
|---|---|
| PubChem CID | 110173700 |
| Molecular Formula | C15H17ClN4O |
| Molecular Weight | 304.78 g/mol |
| Exact Mass | 304.11 |
| IUPAC Name | 7-chloro-12-methoxy-5-methyl-3-(2-methylpropyl)-2,4,8,13-tetrazatricyclo[7.4.0.02,6]trideca-1(9),3,5,7,10,12-hexaene |
| SMILES | COc1ccc2nc(Cl)c3c(C)nc(CC(C)C)n3c2n1 |
| InChI | InChI=1S/C15H17ClN4O/c1-8(2)7-11-17-9(3)13-14(16)18-10-5-6-12(21-4)19-15(10)20(11)13/h5-6,8H,7H2,1-4H3 |
| InChIKey | FPIIGLKSQVZNOB-UHFFFAOYSA-N |
| XLogP | 3.45 |
| TPSA | 52.31 Ų |
| H-Bond Donors | |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 3 |
| Heavy Atoms | 21 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 304.78 |
| LogP ≤ 5 | 3.45 |
| H-Bond Donors ≤ 5 | 0 |
| H-Bond Acceptors ≤ 10 | 5 |