C6H11FO5 — CID 51398010
(2R,3R,4R,5S,6R)-6-(fluoromethyl)oxane-2,3,4,5-tetrol (PubChem CID 51398010) has the molecular formula C6H11FO5 and a molecular weight of 182.15 g/mol. Its IUPAC name is (2R,3R,4R,5S,6R)-6-(fluoromethyl)oxane-2,3,4,5-tetrol.
| Compound Name | (2R,3R,4R,5S,6R)-6-(fluoromethyl)oxane-2,3,4,5-tetrol |
|---|---|
| PubChem CID | 51398010 |
| Molecular Formula | C6H11FO5 |
| Molecular Weight | 182.15 g/mol |
| Exact Mass | 182.06 |
| IUPAC Name | (2R,3R,4R,5S,6R)-6-(fluoromethyl)oxane-2,3,4,5-tetrol |
| SMILES | O[C@H]1[C@@H](O)[C@H](O)O[C@@H](CF)[C@H]1O |
| InChI | InChI=1S/C6H11FO5/c7-1-2-3(8)4(9)5(10)6(11)12-2/h2-6,8-11H,1H2/t2-,3+,4+,5+,6+/m0/s1 |
| InChIKey | SHFYXYMHVMDNPY-YDMGZANHSA-N |
| XLogP | -2.24 |
| TPSA | 90.15 Ų |
| H-Bond Donors | 4 |
| H-Bond Acceptors | 5 |
| Rotatable Bonds | 1 |
| Heavy Atoms | 12 |
| Complexity | — |
Passes Rule of Five
| Rule | Value |
|---|---|
| MW ≤ 500 | 182.15 |
| LogP ≤ 5 | -2.24 |
| H-Bond Donors ≤ 5 | 4 |
| H-Bond Acceptors ≤ 10 | 5 |